This is how I sorted the following elementary tasks:
High Level Cognitive Demand: J, M, N
Low Level Cognitive Demand: A, B, C, D, E, F, G, H, I, K, L, O, P
Please keep in mind, I use to be a high school teacher!!! From my frame of reference, I ranked many of the tasks low, however, those of you who work with elementary students on a daily basis have a better frame of reference.
As I reviewed each task, I thought about the thinking involved to solve each of them. For a high level cognitive demand task, I used the following as a criteria: how much reasoning, number of steps to solve, manipulatives, how much information was provided for students, evaluate, analyze, draw conclusions, and non-routine problem. For a low level cognitive demand task, I used the following as a criteria: recall of information, show understanding of concept, use a formula, explain their thinking, and and solve a problem.
In most of the tasks I ranked low, students would show an understanding of the problem. For example, In task C, I ranked that as high, but when I thought about it, students are only demonstrating an understanding of division by providing a real-life situation. Task G may be difficult for students because they have not mastered the steps of division and those are just routine division problems. When I first reviewed task H, I thought the answers could be A and B. Then I reread and realized that the problem said "most" of the students had pockets so it must be B. This task measures how to interpret graphs. In Task K, students had to solve by using a number sentence then explain with a picture or words. This shows understanding of the word problem. Many times, people think because you justify, summarize, or explain it bumps the question to a high level of cognitive demand and that is not always true.
In the tasks I selected for a high level of cognitive demand, there was a level of reasoning that students had to do and there maybe more than one answer or several methods to solve. For example, in Task J, students could have several different answers to the problem. Students need to have an understanding of 1/2 and realize that 1/2 is not the same number for different sizes but it is the same ratio. I am not sure about task M. Would students know what leveling off mean? Maybe this problem is low and the choice of vocabulary would trick students. Let me know what you think.
Saturday, June 28, 2014
Martha’s Carpeting Task and Fencing Task
In the Martha’s Carpeting Task, the cognitive demand is low because the
dimensions are given. Students should
know “long” is the length, “wide” is the width, and Area = Length X Width. I assume the teacher has introduced the area
formula to students; therefore, I would classify this problem as
Recall/Reproduction in Webb’s Depth of Knowledge because students only need to recognize
that “square feet” refers to area in the question and calculate (i.e. multiple
the dimensions) to find the answer.
In the Fencing Task, the cognitive demand is higher because only the
fencing (i.e. perimeter) is given.
Students need to know how perimeter and area are interconnected. Also, students must determine the maximum
area for the rabbits in both situations (i.e. 24 and 16 feet of fencing). I believe students would draw a picture, list
the factors of 24 as well as 16, and use trial and error to find the
answer. Based on their answers in questions 1 and 2,
they must organize their thinking and explain how to determine the most room or
area for any amount of fencing. Thus,
students would describe a strategy on how to derive an answer. Strategies may vary. I
believe this problem would be at the Skill/Concept level in Webb’s Depth of
Knowledge. I also considered the
Strategic level because this problem requires reasoning, drawing conclusions
about how to figure out area for any amount of fencing. This question goes beyond just memorizing a
formula.
Furthermore, I think the cognitive demand of any math problem would
also depend on the instruction. For
example, if the teacher reviewed several types of fencing tasks similar to this
one, then students are just regurgitating what the teacher has already shown
them. Therefore, deep thinking is
removed.
Friday, June 27, 2014
Condominium Problem
Condominium Problem
In a particular condominium community 2/3 of all of the men are married to 3/5 of all of the women. What fraction of the entire condominium community are married?
When I first looked at the problem, I added the two fractions together and got 16/15. I knew that did not seem reasonable. I had to think about it for a moment. Then I realized this is a part to whole problem. The part represents married people and the whole represents everyone in the condominium community. Once this clicked in my mind, I just set the problem up using variables M and W. So this is how I solved it.
M = men 2/3M + 3/5W
W = women M + W
Assumptions: the number of men must equal the number of women; cannot marry yourself so I must have an even number of married people as a final answer
2/3M = 3/5W from this equation I solved for M and got: M = 9/10W
Then I substituted for M in my original equation:
2/3(9/10W) + 3/5W
9/10W + W
Next, I simplified and combined like terms on the top and like terms on the bottom:
6/5W
19/10W
Next, I cancelled out the W's and divided the fractions. My final answer is 12/19. There are 12 married people out of a total of 19 people.
I liked this problem because I had to think and process. I will share it with teachers!
In a particular condominium community 2/3 of all of the men are married to 3/5 of all of the women. What fraction of the entire condominium community are married?
When I first looked at the problem, I added the two fractions together and got 16/15. I knew that did not seem reasonable. I had to think about it for a moment. Then I realized this is a part to whole problem. The part represents married people and the whole represents everyone in the condominium community. Once this clicked in my mind, I just set the problem up using variables M and W. So this is how I solved it.
M = men 2/3M + 3/5W
W = women M + W
Assumptions: the number of men must equal the number of women; cannot marry yourself so I must have an even number of married people as a final answer
2/3M = 3/5W from this equation I solved for M and got: M = 9/10W
Then I substituted for M in my original equation:
2/3(9/10W) + 3/5W
9/10W + W
Next, I simplified and combined like terms on the top and like terms on the bottom:
6/5W
19/10W
Next, I cancelled out the W's and divided the fractions. My final answer is 12/19. There are 12 married people out of a total of 19 people.
I liked this problem because I had to think and process. I will share it with teachers!
Wednesday, June 25, 2014
Introduction
I
am Shannon Register from a little town called Whiteville, NC. I am the middle child of three siblings and I
use to suffer from the “middle child” syndrome.
I thought the world revolve around me until I had my beautiful daughter,
Kaylin. Now, the world revolves around
her. In my spare time which is not much,
I spend it with my husband and daughter. Currently,
my family lives in Fayetteville, NC.
After
graduating from NC State University with a BA in mathematics education and BS
in mathematics, I moved back home to Whiteville and taught high school
mathematics for several years. Then
moved to Fayetteville where I taught for several more years and served as an
assistant principal and principal as well.
I am the newly named Assistant Superintendent
of Secondary Education (Grades 6 – 13) in Hoke County. I have worked in Hoke for the past 7 years
and started in the position of Curriculum Coordinator for Science and
Mathematics in grades 9 – 12. My passion
is mathematics. I LOVE math! I love the challenge of solving problems and problem
solving. When I taught mathematics, I
always had at least 90% of my students proficient on the end-of-course
tests. Everyone would ask “What is your
secret?” I did not have a secret. As I reflect, I believe it was the
relationships that I cultivated with my students. I focused on relationships first then
mathematics. I firmly believed in the
six-point lesson, explicitly teaching problem solving skills, and
standard-based instruction.
In my different roles
as a supervisor of curriculum, I observed different approaches to teaching
mathematics such as textbook-dependent instruction, activity-based instruction,
inquiry-based instruction, etc. I
believe exemplary mathematics teaching is ensuring that instruction is
student-centered to include scaffolding strategies to meet the needs of
students. As mathematicians, we must use a conceptual
understanding framework of mathematics not just memorization of formulas. We must foster curiosity, problem solving
skills, and allow students to discover and make connections to previous
knowledge.
I am very excited
about this course because it will provide me an opportunity to delve into the
pedagogy of mathematics and get a better grasp of conceptual understanding in mathematics and how we as educators need to shift our thinking and instruction
to ensure students are equipped for the 21st century. I am confident in leading in mathematics, however, I want/need to add more tools to my toolbox and assist teachers with making a 21st century shift in the delivery of content.
My two babies! Kaylin (daughter) and Anthony (husband)
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